(5/x-2)-(7/x+2)=12/x^2-4

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Solution for (5/x-2)-(7/x+2)=12/x^2-4 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x-(7/x)-2-2 = 12/(x^2)-4 // - 12/(x^2)-4

5/x-(7/x)-(12/(x^2))-2-2+4 = 0

5/x-7*x^-1-12*x^-2-2-2+4 = 0

-2*x^-1-12*x^-2 = 0

t_1 = x^-1

-12*t_1^2-2*t_1^1 = 0

-12*t_1^2-2*t_1 = 0

DELTA = (-2)^2-(-12*0*4)

DELTA = 4

DELTA > 0

t_1 = (4^(1/2)+2)/(-12*2) or t_1 = (2-4^(1/2))/(-12*2)

t_1 = -1/6 or t_1 = 0

t_1 = -1/6

x^-1+1/6 = 0

1*x^-1 = -1/6 // : 1

x^-1 = -1/6

-1 < 0

1/(x^1) = -1/6 // * x^1

1 = -1/6*x^1 // : -1/6

-6 = x^1

x = -6

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -6

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